Question

I don’t know these so please help me out

Answer 1

`BF=45`

Explanation:

In the triangle
`ABF` and triangle
`ACE`

`BF||CE\\ \Rightarrow \angle ABF=\angle ACE\\ \Rightarrow \angle AFB=\angle AEC\\ \angle A=\angle A`

Hence from
`AAA\ \`
`\Delta ABF\cong \Delta ACE`

`(BC)/(CE)=(AB)/(AC)\\(BF)/(CE)=(AB)/(2AB)\\BF=(1)/(2)* CE\\BF=(1)/(2)* 90\\BF=45`