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How many solutions are there to the system of equations? StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negative 0.08 x + 0.10 y = 0.10 EndLayout no solutions one solution two solutions an infinite number of solutions

2 Answers

3 votes

Answer:

im pretty sure the answer is b: one answer only

Explanation:

cuz it work

User Kaskader
by
7.6k points
5 votes

Answer:

Only one solution
x=(5)/(4),y=0

Explanation:


4x-5y=5..............(1)\\0.08x+0.10y=0.10...........(2)

Multiply equation
(2) by
50


4x-5y=5........(3)

Now from equation
(1)
+ equation
(3)


8x=10\\x=(10)/(8)\\x=(5)/(4)

Put the value in equation
(1)


5-5y=5\\5y=0\\y=0

hence only one solution exists
\left((5)/(4),0\right).

User Matthew Lundberg
by
8.0k points