Question

"A sample of air at 7.50 atm is cooled from 448K to 224K. If the volume remains constant, what is the final pressure?

Answer 1

P/T = constant (T = absolute temperature)

P1 = 7.5 atm

T1 = 224 K

P2 = ?

T2 = 448 K

P1/T1 = P2/T2

P2 = (T2/T1)*P1 = (448/224)*(7.5 atm) = 15.00 atm

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Applying gas law formulae:

P1/T1 = P2/T2

Where P1 = initial pressure (atm) = 7.5

T1 = initial temperature in Kelvin(K) = 448

P2 = final pressure (atm) = unknown

T2 = final temperature in Kelvin(K) = 224

From the above Formula make P2 the subject of formula

P2 = P1T2/T1

P2 = 7.50*224/448

P2 = 1680/448

P2 = 3.75ATM