Question

In Fairlawn, there are $5000$ households with an average of $2.26$ people per household. Of these households, $1400$ are single-person households and the rest are multiple-person households. On average, how many people are in each multiple-person household?

Answer 1

2.75 people in each multiple-person household.

Step-by-step explanation:

If 5000 households average 2.26 people, then there are (5000 x 2.26) =11300 people.

If 1400 of 5000 households are single-person, 3600 are multiple-person.

Of the 11300 people, 1400 live in single-person households, so (11300-1400) = 9900 people live in 3600 multiple-person households.

This comes to an average of 9900 people/3600 households or 2.75 people per household.

Therefore, there is an average of 2.75 people in each multiple-person household.

Answer 2

2.75

Step-by-step explanation:

With 5,000 households in total, and

2.26 average number of occupants,

Total number of occupants = 5,000 * 2.26 = 11,300

Single-Person Households

With 1,400 single-person households in total, and

1 average number of occupants (single-person are 1-person occupied),

Total number of occupants in single-person households = 1,400 * 1 = 1,400.

Multi-Person Households

The number of households and occupants in multi-person households will be derived by subtracting single-person data from the total number.

Multi-person households = total households - single-person households

= 5,000 - 1,400 = 3,600

Total number of occupants in multi-person households = total number of occupants of all households, less total number of occupants (single-person households)

= 11,300 - 1,400 = 9,900

Therefore, the number of people in each multi-person household

= (total number of occupants in multi-person households)/(total number of multi-person households)

= 9,900/3,600

= 2.75