Step-by-step explanation:
Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184
Then, the stations N share 56 kbps
And, the channel rate =
Then, the outputs of the wach stations is
![1000-bit frames/100 sec](https://img.qammunity.org/2020/formulas/computers-and-technology/college/j04zyl3aijz6pyqmis2678s44g2elvzh41.png)
, the output of the bits/ sec by each stations =
![(1000)/(100) bits/sec = 10 bits/sec](https://img.qammunity.org/2020/formulas/computers-and-technology/college/76publvx38s9x1gy7pvnhn19ih32fzc3ey.png)
So, The output of the N stations is 10 bits/sec on the channel that having
![10.304kb/sec](https://img.qammunity.org/2020/formulas/computers-and-technology/college/fjge56f5kyout9o43a5juuqy0530nozqqk.png)
Finally, N =
![((10.304 * 10^(3)))/(10) = 1030 stations](https://img.qammunity.org/2020/formulas/computers-and-technology/college/lsyxvs986px90n0x4jppsu5dj8iiefpayo.png)