Question

A car with mass 1600 kg drives around a flat circular track of radius 28.0 m. The coefficient of friction between the car tires and the track is 0.830. The car is traveling at the maximum speed possible without losing traction.

Answer 1

v=15.24 m/s

Step-by-step explanation:

Given that

Mass ,m= 1600 kg

radius ,r= 28 m

Coefficient of friction ,μ = 0.83

The radial force on the car when it takes turn

`F=(mv^2)/(r)`

The friction force on the car

Fr= μ m g

The condition for motion without losing traction

F= Fr

`(mv^2)/(r)=\mu\ m g`

v²=μ r g

`v=√(\mu\ r g)`

Now by putting the values

`v=√(0.83* 28* 10)\ m/s` ( take g=10m/s²)

v=15.24 m/s

The speed of the car will be 15.24 m/s