Question

According to the National Telecommunication and Information Administration, 56.5% of U.S. households owned a computer in 2001. What is the probability that of three randomly selected U.S. households at least one owned a computer in 2001?

Answer 1

To find the probability that at least one of three randomly selected U.S. households owned a computer in 2001, we use the complement rule. The probability is approximately 75.23%.

Step-by-step explanation:

To find the probability that at least one of three randomly selected U.S. households owned a computer in 2001, we will use the complement rule. The complement of at least one household owning a computer is that none of the households owned a computer.

From the given information, we know that 56.5% of U.S. households owned a computer in 2001. Therefore, the probability that none of the three households owned a computer is (1-0.565)^3 = 0.2477.

Finally, we subtract this probability from 1 to find the probability that at least one household owned a computer, which is 1-0.2477 = 0.7523, or approximately 75.23%.