Question

A string of linear density 1.5 g/m is under a tension of 20 N. What should be its length if its fundamental resonance frequency is 220 Hz

Answer 1

L= 0.262 m

Step-by-step explanation:

Given that

Linear velocity ,μ = 1.5 g/m

μ = 1.5 x 10⁻³ Kg/m

Tension ,T= 20 N

Fundamental Frequency ,f= 220 Hz

We know that fundamental frequency given as

`f=(1)/(2L)*\sqrt{ (T)/(\mu)}`

L=length

Now by putting the values

`L=(1)/(2f)*\sqrt{ (T)/(\mu)}`

`L=(1)/(2* 220)*\sqrt{ (20)/(1.5* 10^(-3))}`

L= 0.262 m

Therefore the length will be 0.262 m.