Answer:
The volume of air after the balloon is heated = 1.95 × 10⁶ L
Step-by-step explanation:
Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.
It can be expressed mathematically as,
V₁/T₁ = V₂/T₂
Making V₂ The subject of the equation
V₂ = (V₁/T₁)T₂.................... Equation 1
Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature
Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.
Substituting these values into equation 1 above,
V₂ = (1.45×10⁶)382/284
V₂ = 1.95 × 10⁶ L
Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L