Question

With what minimum speed must you toss a 110 g ball straight up to just touch the 11-m-high roof of the gymnasium if you release the ball 1.3 m above the ground?

Answer 1

v = 13.79 m/s

Step-by-step explanation:

given,

mass of ball = 110 g

height = 11 m

ball is released from = 1.3 m

minimum speed = ?

using conservation of energy

Potential energy is conserved in the form of kinetic energy

`P E =KE`

`m g h= (1)/(2)mv^2`

`v^2 = 2 g h`

`v=√(2 g h)`

`v=√(2* 9.8 * (11-1.3))`

`v=√(2* 9.8 * 9.7)`

`v=√(190.12)`

v = 13.79 m/s