Answer:
$43.20
Explanation:
If each family member buys one ticket and one lunch, then for ticket price t we have the total expenditure as ...
5(t +6.50) = 248.50
t +6.50 = 49.70 . . . . . divide by 5
t = 43.20 . . . . . . . . . . subtract 6.50
The price of each train ticket is $43.20.