Question

A very long wire carries a uniform linear charge density of 5 nC/m. What is the electric field strength 13 m from the center of the wire at a point on the wire's perpendicular bisector? (ε 0 = 8.85 × 10-12 C2/N · m2)

Answer 1

E=6.91 N/C

Step-by-step explanation:

Given that

Linear Charge density ,λ = 5 nC/m

Distance ,R= 13 m

We know that formula for long wire to find electric field

`E=(\lambda )/(2\pi \varepsilon _0R)`

E=Electric field

R=Distance

εo=8.85 x 10⁻¹² C²/N.m²

λ=Linear Charge density

Now by putting the values

`E=\frac{5* 10^(-9)}{{2* \pi * 8.85* 10^(-12)* 13}}`

E=6.91 N/C

Therefore the electric filed at distance 13 m will be 6.91 N/C