Question

Nitrogen:0.781 oxygen:0.209 argon: 0.010 (Mole fraction)

What is the partial pressure or nitrogen (in torr) in the atmosphere when the atmospheric pressure is 765.0 torr?

Answer 1

The partial pressure of nitrogen is 597.5 torr

Step-by-step explanation:

Step 1: Data given

Mol fraction of N = 0.781

Mol fraction of O = 0.209

Mol fraction Ar = 0.010

Atmospheric pressure = 765.0 torr

The partial pressure is given by Pi = Xi * Pt

⇒ χ i = the mole fraction of gas i in the mixture

⇒ P total = the total pressure of the mixture

Step 2: Calculate the partial pressure of nitrogen

P(N) = mol fraction of N * atmospheric pressure

P(N) = 0.781 * 765.0 torr = 597.5 torr

The partial pressure of nitrogen is 597.5 torr