Question

Scores on a dental anxiety scale range from 0​ (no anxiety) to 20​ (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the​ z-score for the given score on this dental anxiety scale.

Answer 1

`z_(score) = \displaystyle(x-\mu)/(\sigma)`

Explanation:

The following information is missing in the question:

We have to find z-score for the given score on this dental anxiety scale: 12, 6

We are given the following information in the question:

Mean, μ = 11

Standard Deviation, σ = 4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

`z_(score) = \displaystyle(x-\mu)/(\sigma)`

where x is the given score on this dental anxiety scale.

For x = 12

`z_(score) = \displaystyle(12-11)/(4) = 0.25`

For x = 6

`z_(score) = \displaystyle(6-11)/(4) = -1.25`