Question

(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Answer 1

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

`BW = F_(c2)-F_(c1)`

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

`BW = (88-5)kHz`

`BW = 83kHz`

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

`f_0 = \sqrt{f_(c1)*f_(c2)}`

`f_0 = √(88*5)`

`f_0 = 20.97kHz`