Answer:
70 mph in only 168 feet is the largest
Step-by-step explanation:
In which of those three situations is the magnitude of the car's acceleration the largest? In which of those three situations is the magnitude of the car's acceleration the largest? cornering at 0.85g reaching 60 mph in 5 seconds flat stopping from 70 mph in only 168 feet not enough information to determine
a) convert miles/hour to ft/seconds
60mph
1 mile=5280ft
1hr=3600secs
= 60 * 5280 / 3600 ft/s
=> acceleration
acceleration is the rate of change in velocity
= [60 * 5280 / 3600] / 5 ft/s^2
= 264/15 ft/s^2
= 264/(15 * 32) g
= 0.55 g
magnitude of acceleration in case 2
= 0.85 g
magnitude of acceleration in case 3
recall from

u=0
v^2/2s=a
velocity , a=acceleration
s=distance covered
= (70 * 5280 / 3600)^2 / (2 * 168 * 32) g
= 0.98 g
=> largest magnitude of acceleration = 0.98 g in case 3
and smallest magnitude of acceleration = 0.55 g in case 1.