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To save money on buying mercury you build a BAROMETER using water as the fluid inside the column. Approximately, how tall is your barometer? (HINTS r(mercury) =1.36 x 10^4 kg/m^3 and r(water) = 1.00 x 10^3 kg/m^3).

User Gatonito
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To solve this problem we need to use the concepts related to fluid density. Since we need to know a height point of two different liquids, their pressures must be equal, so


P_1 = P_2


\rho_1 gh_1 = \rho_2gh_2

Where,


\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as,


\rho_1 = 1.36*10^4kg/m^3


\rho_2 = 1*10^3kg/m^3


h = 76.02cm \rightarrow Standard mercury pressure at 1atm, the barometer height is 760.2mm.

Replacing we have,


1.36*10^4 *76.02= 10^3*h_2


h_2 = 1033.87cm

Therefore the tall of the barometer would be 1033.87 (Inconvenient compared with the Mercury Barometer)

User MrSpaar
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