Question

If you purchased 0.610 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?Express your answer numerically in disintegrations per second.

Answer 1

the sample undergo
`1.67 * 10^5` disintegrations per second.

Step-by-step explanation:

Given:

The amount of sulphur purchased is 0.671 μCi

To find:

disintegrations per second = ?

Solution:

Some of the conversions are

`1 Ci = 3.8 * 10^(10) Bq`

1 rad = 0.01 Gy

1Gy = 1 j/kg tissue

1 rem = 0.01 Sv

1Sv = 1 j/Kg

Using these conversions,

The decay rate of this sample is calculated as

`0.671 \mu C i * (1 \mu C i)/(10^(6)) \mu C i * (0.671 * 10^(10))/(1 \mu C i)`

=
`1.67 * 10^5` disintegrations per second