Explanation:
we have
∠CAX=∠BAX
AC=AB
[AX] a common side for both triangles ΔACX and ΔABX
then
ΔACX and ΔABX are two isometric triangles
therefore XC=XB
then the triangle ΔXBC is isoceles
then ∠XBC ≡ ∠XCB.
:)
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