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5 votes
Find three positive consecutive even integers such that the product of the first and second is 8 more than 38 times the third

The three integers, in ascending order, are ___, ____, and____

1 Answer

3 votes

Answer:

40, 42, 44

Explanation:

x, x+2, x+4 are the 3 positive consecutive integers.

x(x+2)=8+38(x+4)

x^2+2x=8+38x+152

x^2+2x-38x-8-152=0

x^2-36x-160=0

(x-40)(x+4)=0.

x-40=0

x=40 1st integer.

40+2=42 2nd integer.

40+4=44 3rd integer.

Proof:

40*42=8+38*44

1680=8+1672

1680=1680.

Best of Luck to you.

If you have any questions, feel free to comment below.

Have a Happy New Year.

User Torrey
by
8.5k points

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