Answer:
The mol fraction of nitrogen is 0.787
Step-by-step explanation:
Step 1: Data given
Partial pressure of nitrogen = 592 torr
Air pressure = 752 torr
Step 2: Calculate mol fraction
P1/PT = n1/nT = mol fraction
⇒ P1 = the partial pressure of nitrogen = 592 torr
⇒ PT = The total pressure = air pressure = 752 torr
⇒ n1 = number of mol of nitrogen
⇒ nT = Total number of mol
Mol fraction of nitrogen in air = 592/752 = 0.787
The mol fraction of nitrogen is 0.787