Question

Two long, parallel wires are separated by a distance of 3.40 cm . The force per unit length that each wire exerts on the other is 3.60×10−5 N/m , and the wires repel each other. The current in one wire is 0.640 A

Answer 1

Current in second wire,
`I_2=9.562\ A`

Step-by-step explanation:

It is given that,

Separation between two parallel wire,
`d=3.4\ cm=3.4* 10^(-2)\ m`

Force per unit length each wire exerts on the other is,
`(F)/(l)=3.6* 10^(-5)\ N/m`

Current in wire 1,
`I_1=0.64\ A`

Let
`I_2` is the current in other wire. The force acting per unit length is given by :

`(F)/(l)=(\mu_o I_1I_2)/(2\pi d)`

`I_2=(2\pi d)/(\mu_oI_1)* (F)/(l)`

`I_2=(2\pi* 3.4* 10^(-2))/(4\pi * 10^(-7)* 0.64)* 3.6* 10^(-5)`

`I_2=9.562\ A`

So, the current in the second wire is 9.562 A. Hence, this is the required solution.