Answer:2625 ways
Explanation:
Given
There are 7 males , 5 Females and 6 children
There are 3 males Roles, 1 Female and 2 child roles available
No of ways in which 3 males can be chosen
![=^(7)C_3=35\ ways](https://img.qammunity.org/2020/formulas/mathematics/college/wktxwa650hoxnyj00veuc5330djwvlki7a.png)
No of ways in which 1 Female can be chosen
![=^(5)C_1=5\ ways](https://img.qammunity.org/2020/formulas/mathematics/college/n3764vki8iinqawi1k6o1ytq7pt720jeqa.png)
No of ways in which 2 children can be chosen
![=^(6)C_2=15\ ways](https://img.qammunity.org/2020/formulas/mathematics/college/ap2j7dl36sdwaochkoeoayhxzepo7l4o44.png)
Total no of ways
![=35* 5* 15=2625\ ways](https://img.qammunity.org/2020/formulas/mathematics/college/sg4waoprp74n96t7pcw6cwna4fr9nsopy7.png)