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What is a mirror's radius of curvature if cars 17.0 m away appear 0.35 their normal size? Follow the sign conventions.

User PMende
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1 Answer

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Answer:

The Mirror's radius of curvature is 18.45 m

Step-by-step explanation:

Radius of curvature (R) = 2 x Focal length (F)

Focal length = R / 2

Object distance (u) = 17 m

magnification = image distance (v) / Object distance (u)

0.35 = v / u

v = 0.35 u

Mirror formula

1 / F = 1 / u + 1 / v

1 /F = 1 /17 + 1 / -0.35u

1/F = 1/17 + 1 / -5.98

1/F = 1 /17 - 1 /5.98

1 / F = - 0.1084

F = - 9.225 m

Focal length is negative because the image formed is virtual.

Recall that: Radius of curvature (R) = 2 x Focal length (F)

= 2 x 9.225

Radius of curvature (R) = 18.45 m

User Marekinfo
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