Answer:
horizontal distance on moon > horizontal distance on earth
Step-by-step explanation:
Let the time of fall is t and the height from which they fall is h.
The time of fall is
![t=\sqrt{(2h)/(g)}](https://img.qammunity.org/2020/formulas/physics/college/o35r7p1h2jsa3piok4yj0xh4e8jhnfmvvq.png)
Time of fall on earth
![t=\sqrt{(2h)/(g_(e))](https://img.qammunity.org/2020/formulas/physics/college/hwt4gd3mi4fw03faaxdt4lod539ys7q0f3.png)
Time of fall on moon
![t'=\sqrt{(2h)/(g_(m))](https://img.qammunity.org/2020/formulas/physics/college/f4u0l0dvmsn6bm9nohxjl50udd2nuq6nf8.png)
As the gravity on moon is less than the gravity on earth
So, t' > t
Horizontal distance = horizontal velocity x time
So, the horizontal distance on moon is more than the horizontal distance on earth.