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Pls really need help with chemistry questions :((

Pls really need help with chemistry questions :((-example-1

2 Answers

7 votes

Answer:

6. 13.8 moles

7. 0.751 moles

8. 2.04 moles

9. 0.00794 moles

10. 0.158 moles

Step-by-step explanation:

User Ferdinando
by
3.4k points
9 votes

Answer:

6. 13.8 moles

7. 0.751 moles

8. 2.04 moles

9. 0.00794 moles

10. 0.158 moles

Step-by-step explanation:

When converting from atoms to moles, use Avogadro's number.

Avogadro's number is 6.02 x 10^23.

After that, then use dimensional analysis for every problem to show your work.

6. (8.31 x 10^24 atoms of magnesium) * 1 mol Mg / (6.02 x 10^23) atoms = 13.80398671.

With sig figs however, it rounds to 13.8. Therefore, there are 13.8 moles of magnesium.

7. (4.52 x 10^23 formula units NaCl) * 1 mol NaCl / (6.02 x 10^23) atoms = 0.750830565.

With sig figs however, it rounds to 0.751. Therefore, there are 0.751 moles of NaCl.

8. (1.23 x 10^24 molecules CO) * 1 mol CO/ (6.02 x 10^23) atoms = 2.043189369.

With sigs figs however, it rounds to 2.04. Therefore, there are 2.04 moles of CO.

9. (4.78 x 10^21 molecules O2) * 1 mol O2 / (6.02 x 10^23) atoms = 0.007940199.

With sigs figs however, it rounds to 0.00794. Therefore, there are 0.00794 moles of O2.

10. (9.50 x 10^22 atoms of C) * 1 mol C / (6.02 x 10^23) atoms = 0.157807309.

With sig figs however, it rounds to 0.158. Therefore, there are 0.158 moles of C.

Hope it helped! Did I explain better than your teacher?

User Ingus
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3.9k points