Question

A 5.0 kg box accelerates to the left while on the floor. It accelerates with a net force of 100 N (in spite of the 200 N of friction it encounters). What is the name of the force that accelerates the box?

Answer 1

Step-by-step explanation:

Given

mass of box
`m=5 kg`

Net force
`F_(net)=100 N`

frictional Force
`f_r=200 N`

using FBD

`F-f_r=F_(net)`

`F_(net)=ma_(net)`

So the force acting on block which accelerates it is Net force

Answer 2

Net force.

Step-by-step explanation:

Given that

m = 5 kg

Net force ,F(net) = 100 N

Friction force ,Fr= 200 N

From the second law of Newton's

F(net) = m a

m= Mass

a= acceleration

F(net) = Net force act on the body

Therefore we can say that, the name of the force that will accelerate the box will be a Net force.

That is why the answer will be Net force.