Question

A steam engine (assume a Carnot engine ) has an efficiency of 50.8%. If the waste heat has a temperature of 72.4 ◦C, what is the temperature of the boiler? Answer in units of ◦C.

Answer 1

429.033 °C

Step-by-step explanation:

We use the equation
`n=(Th-Tc)/(Th)` to find the efficiency. So we'll plug in our values.

`0.508=(Th-345.4)/(Th)` , 345.4 is the waste heat converted to Kelvin

Solve for Th and you get Th=702.033. Convert back to Celcius to get:

Th=429.033 °C