Question

A very long wire carries a uniform linear charge density of 6 nC/m. What is the electric field strength 10 m from the center of the wire at a point on the wire's perpendicular bisector? (ε 0 = 8.85 × 10-12 C2/N · m2)

Answer 1

E = 10.8 N/C

Step-by-step explanation:

given,

uniform linear charge density = 6 n C/m

distance = 10 m

ε₀= 8.85 × 10⁻¹² C²/N ·m²

Electric field at distance R

`E = (2k\lambda)/(R)`

K is coulomb constant

λ is linear charge density

R is the distance

k = 9 x 10⁹

`E = (2* 9 * 10^(9)* 6 * 10^(-9))/(10)`

E = 10.8 N/C