Answer:d
Step-by-step explanation:
Torque of Frictional force will be zero
![\tau _(f_1)=zero](https://img.qammunity.org/2020/formulas/physics/college/pz5xbzmf4rxreyhs5t2xkbyf3togzxs3e4.png)
![\tau_(f_2)=zero](https://img.qammunity.org/2020/formulas/physics/college/drb9jlma9ata3acw7uz4w7pbn85q40z7ks.png)
because they passes through line of action
Torque of Weight is
![T=W* x](https://img.qammunity.org/2020/formulas/physics/college/otc1rom8mqhr63u8294ah1nbbvtf9cstkn.png)
The other force which will create torque about Pivot point is Normal Force on second tire
Torque due to Normal Reaction
![\tau _N=N_2* y](https://img.qammunity.org/2020/formulas/physics/college/eodf8l6ituuzn9q8t2js11nwlaghl1d00k.png)
Thus Normal Force on back tires of car will create torque about this same axis.