Answer:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408
Explanation:
For this problem the sample size is large enough (n>30), and then the sampling distribution
would be approximately normal. The mean of the sampling distributions is given by
![p=0.52](https://img.qammunity.org/2020/formulas/mathematics/college/wiq4mysuceuvikyvztricm3my4xg762qyt.png)
The expected value for the sampling distribution would be 0.52 since
![E(\hat p) = p](https://img.qammunity.org/2020/formulas/mathematics/college/chi5gl6rc1vfknrxt9wgeo203i1krublx1.png)
And for the standard deviation we know that is given by:
![Sd= \sqrt{(p (1-p))/(n)}=\sqrt{(0.52(1-0.52))/(150)}=0.0408](https://img.qammunity.org/2020/formulas/mathematics/college/50bg1i7yf41z3ves4h8wxwxfnrtvj1hgk2.png)
So the correct answers on this case are:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408