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By throwing a ball at an angle 45 degrees a girl can throw the ball a maximum horizontal distance R on a level field How ar can se throw the same ball vertically upward assume that her muscles give the ball the same speed in each case. (Is this assumption valid?)

User Akash Kava
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Answer:

Step-by-step explanation:

Given

Initial launch angle
\theta =45^(\circ)

Suppose u is the initial launching velocity

Range of Projectile is given by


R=(u^2\sin 2\theta )/(g)

thus value of
u^2=(Rg)/(\sin 2\theta )

If this ball is thrown vertically upward with u

then maximum height reached is


h=(u^2)/(2g)


h=((Rg)/(\sin 2\theta ))/(2g)


h=(R)/(2\sin 2\theta )

User Ololo
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