Question

Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume the chicken is mostly water, starts at 0 ∘C, and that it must reach an internal temperature of 170∘ F in order to be cooked.

Answer 1

n= 16021.03 slaps

Step-by-step explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒
`mc\Delta T= n(1)/(2)m_hv_h^2`

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

`1*4180(76.66)= n(1)/(2)0.4*10^2`

n= 16021.03 slaps