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Factor the following polynomial completely. - x2y2 + x4 + 9 y2 - 9 x2 ( x - 3)( x - 3)( x + y )( x - y ) ( x + 3)( x + 3)( x + y )( x - y ) ( x + 3)( x - 3)( x + y )( x - y )

2 Answers

3 votes

Answer:

(x +3)(x -3)(x +y)(x -y)

Explanation:

User Smithclay
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Answer:

( x + 3)( x - 3)( x + y )( x - y )

Explanation:

You can group the terms in pairs and factor each pair:

-x^2y^2 + x^4 + 9y^2 - 9x^2 = x^2(-y^2+x^2) -9(-y^2+x^2)

= (x^2 -9)(x^2 -y^2)

Each of these factors is the difference of squares, so can be factored as such:

= (x +3)(x -3)(x +y)(x -y)

User Outcassed
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