Question

A 0.450 kg ball of Play-Doh hangs from the ceiling by a string. A 0.0850 kg wad of Play-Doh is thrown straight upward from below the ball and strikes the ball with a speed of 6.40 m/s and sticks to it. How high does the combined mass of Play-Doh rise above the original position of the ball of Play-Doh?

Answer 1

0.05269 m

Step-by-step explanation:

`m_2` = Mass of play doh thrown = 0.085 kg

`m_1` = Hanging mass of play doh = 0.45 kg

v =Combined velocity

u = Speed of play doh = 6.4 m/s

As the momentum of the system is conserved we have

`m_2u=(m_1+m_2)v\\\Rightarrow v=(m_2u)/(m_1+m_2)\\\Rightarrow v=(0.085* 6.4)/(0.45+0.085)\\\Rightarrow v=1.01682\ m/s`

Height of the combined mass is given by

`h=(v^2)/(2g)\\\Rightarrow h=(1.01682^2)/(2* 9.81)\\\Rightarrow h=0.05269\ m`

The height to which the combined mass will rise is 0.05269 m