Question

A thin spherical shell has a radius of 1.49 m and a mass of 135 kg . g g g g g g g g g g g g r = 1.49 m M = 135 kg hollow shell What is the gravitational field 3.71 m from the center of the shell? The universal gravitational constant is 6.6726 × 10−11 N m2 /kg2 . Answer in units of N/kg.

Answer 1

6.54 x 10^-10 N/kg

Step-by-step explanation:

mass of the shell, M = 135 kg

radius of shell, R = 1.49 m

distance from the centre of the shell, r = 3.71 m

The gravitational filed is given by

`E = (GM)/(r^(2))`

`E = \frac{6.67*10^(-11)*135){3.71*3.71}}`

E = 6.54 x 10^-10 N/kg

Thus, the gravitational field intensity at a distance 3.71 m is 6.54 x 10^-10 N/kg.