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(x^a)^b-c*(x^b)^c-a*(x^c)^a-b

User Kimmarie
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2 Answers

1 vote
Refer to the attachment
(x^a)^b-c*(x^b)^c-a*(x^c)^a-b-example-1
User Khawar Raza
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2 votes

Answer =1

Explanation:

(xᵃ)ᵇ⁻ⁿ(xᵇ)ⁿ⁻ᵃ(xⁿ)ᵃ⁻ᵇ (here n=c)

=xᵃᵇ⁻ᵃⁿ. xᵇⁿ⁻ᵇᵃ. xⁿᵃ⁻ⁿᵇ

=xᵃᵇ⁻ᵃⁿ⁺ᵇⁿ⁻ᵇᵃ⁺ⁿᵃ⁻ⁿᵇ

=x⁰=1

User Gsempe
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