Question

Find the equation of a side AB of △ABC whose vertices are A(1,4) B (2,-3) and C(-1,-2)​

Answer 1

`\displaystyle\bf\\A(1,4),~B(2,-3),~C(-1,-2)\\Equation~of~a~side~AB~is:\\\\(x-B_x)/(A_x-B_x)=(y-B_y)/(A_y-B_y)\\\\\\(x-2)/(1-2)=(y-(-3))/(4-(-3))\\\\\\(x-2)/(-1)=(y+3)/(7)\\\\\\7(x-2)=-1(y+3)\\\\7x-14=-y-3\\\\7x-14+y+3=0\\\\7x+y-14+3=0\\\\\boxed{\bf7x+y-11=0}`