Question

What is the total volume of gaseous products formed when 98.1 liters of butane (C4H10) react completely according to the following reaction? (All gases are at the same temperature and pressure.) butane (C4H10) (g) + oxygen (g) carbon dioxide (g) + water (g)

Answer 1

Total volume of gaseous products = 882.9 L

Step-by-step explanation:

The balanced equation for combustion of butane is:

`C_4H_(10)+(13)/(2) O_(2)\ --->\ 4CO_(2)+5H_2O`

At constant temperature and pressure volume of gas is directly proportional to number of moles of the gas.

Then from the balanced equation we can say that:

1 L of butane reacts with 6.5 L of oxygen to give 4 L of carbon dioxide and 5 L of water.

98.1 L of butane gives 4*98.1 L of carbon dioxide and 5*98.1 L of water.

Hence total volume of gaseous products formed = 98.1*(4+5) L

= 98.1*9 L = 882.9 L