Question

Two moles of helium gas initially at 438 K and 0.44 atm are compressed isothermally to 1.61 atm. Find the final volume of the gas. Assume that helium behaves as an ideal gas. The universal gas constant is 8.31451 J/K · mol.

Answer 1

44.64335 L

Step-by-step explanation:

R = Gas constant = 8.314 J/mol K = 0.08205 L atm/mol K

P = Pressure

V = Volume

T = Temperature = 438 K

1 denotes initial

2 denotes final

From ideal gas law we have

`PV=nRT\\\Rightarrow V=(nRT)/(P)\\\Rightarrow V=(2* 0.08205* 438)/(0.44)\\\Rightarrow V=163.35409\ L`

So,

`P_1V_1=P_2V_2\\\Rightarrow V_2=(P_1V_1)/(P_2)\\\Rightarrow V_2=(0.44* 163.35409)/(1.61)\\\Rightarrow V_2=44.64335\ L`

The volume of Helium is 44.64335 L