Question

What acceleration does it take to reach 15 m/s (from rest) in 5 seconds?

Answer 1

The acceleration needed to reach 15 m/s from rest in 5 seconds is 3 m/s².

Step-by-step explanation:

To calculate the acceleration required for an object to reach a final velocity from an initial velocity in a certain amount of time, we can use the formula:

`a = (v_f - v_i) / t`

where:
a = acceleration (in m/s²)

`v_f` = final velocity (in m/s)

`v_i`= initial velocity (in m/s)
t = time (in seconds).

In this problem, the object starts at rest (
`v_i` = 0 m/s) and reaches a velocity of 15 m/s (
`v_f` = 15 m/s) in 5 seconds (t = 5 s). Plugging these values into the formula, we get:

a = (15 m/s - 0 m/s) / 5 s = 3 m/s².

So, the average acceleration needed is 3 m/s².

Answer 2

The answer is simple….

As we know v = u + (a×t)

Where

v is the final velocity

u is the initialvelocity

a is the acceleration

t is the time taken

So according to the question:-

u=0, v=15 , a=3 and we have to find t…

So the equation is written as:-

15 = 0 + (3×t)

=> t = (15 ÷ 3) = 5

Therefore, the time required is 5 seconds..