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Mr. Mole left his burrow and started digging his way down at a constant rate. Time (minutes) Altitude (meters) 666 -20.4−20.4minus, 20, point, 4 999 -27.6−27.6minus, 27, point, 6 121212 -34.8−34.8minus, 34, point, 8 What is the altitude of Mr. Mole's burrow?

User Alborozd
by
5.9k points

2 Answers

1 vote

Answer:

its 6 not -6

Explanation:

User Cumulo Nimbus
by
4.8k points
1 vote

Answer:


-6 meters.

Explanation:

We have been given Mr. Mole left his burrow and started digging his way down at a constant rate.

We are also given a table of data as:

Time (minutes) Altitude (meters)

6 -20.4

9 -27.6

12 -34.8

First of all, we will find Mr. Mole's digging rate using slope formula and given information as:


m=(y_2-y_1)/(x_2-x_1), where,


y_2-y_1 represents difference of two y-coordinates,


x_2-x_1 represents difference of two corresponding x-coordinates of y-coordinates.

Let
(6,-20.4) be
(x_1,y_1) and
(9,-27.6) be
(x_2,y_2).


m=(-27.6-(-20.4))/(9-6)


m=(-27.6+20.4)/(3)


m=(-7.2)/(3)


m=-2.4

Now, we will use slope-intercept form of equation to find altitude of Mr. Mole's burrow.


y=mx+b, where,

m = Slope,

b = The initial value or the y-intercept.

Upon substituting
m=-2.4 and coordinates of point
(6,-20.4), we will get:


-20.4=-2.4(6)+b


-20.4=-14.4+b


-20.4+14.4=-14.4+14.4+b


-6=b

Since in our given case y-intercept represents the altitude of Mr. Mole's burrow, therefore, the altitude of Mr. Mole's burrow is
-6 meters.

User Rawand Saeed
by
5.7k points