Question

A 0.016-kg piece of iron absorbs 1086.75 joules of heat energy, and its

temperature changes from 25°C to 175°C. Calculate the specific heat
capacity of iron. Equation : c = Q/mt

Answer 1

c = 115.92 q/g C

Step-by-step explanation:

0.016 kg = 16 grams

q = Joules

m = mass (g)

t = (final temp. - initial temp)

c = specific heat

c = (1086.75 joules) / (175 C - 25 C) (16 g)

c = 115.92 q/g C