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A football player at practice pushes a 60 kg blocking sled across the field at a constant speed. The coefficient of kinetic friction between the grass and the sled is 0.30.

How much force must he apply to the sled?

A. 18 N

B. 60 N

C. 180 N

D. 600 N

1 Answer

3 votes

Answer:

C. 180 N

Step-by-step explanation:


m = mass of the blocking sled = 60 kg


\mu = Coefficient of kinetic friction = 0.30


f = kinetic frictional force acting on the sled

kinetic frictional force acting on the sled is given as


f = \mu mg = (0.30) (60) (10) = 180 N


F =Force applied

For the sled to move at constant speed, the applied force must be same as the frictional force


F = f\\F = 180 N

User Jaydeep Purohit
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