Question

On a coordinate plane, a triangle has points J (negative 3, 9), L (negative 3, 2), and K (5, 2).

Consider reflections of ΔJKL.


What line of reflection maps point K to point K' at (–5, 2)?

Answer 1

The line of reflection that maps point K to point K' in this scenario is the y-axis, since it is equidistant from both points on the coordinate plane.

Step-by-step explanation:

The student is asking how to find a line of reflection that would map a point on a triangle to its reflected point on a coordinate plane. Specifically, they want to know the line of reflection that maps point K at (5, 2) to point K' at (-5, 2).

The line of reflection that accomplishes this would be a vertical line that is equidistant from both K and K'. The x-coordinates differ in sign but are equal in absolute value, which tells us that our line of reflection lies exactly in the middle at x=0.

Therefore, the line x=0, which is the y-axis, is the line of reflection that maps point K to point K'.

Answer 2

What line of reflection maps point K to point K' at (–5, 2)?

✔ y-axis

What line of reflection maps point L to point L' at (–2, 3)?

✔ y = -x