Question

The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by LaTeX: h\left(t\right)\:=\:-16t^2+64t+12.h ( t ) = − 16 t 2 + 64 t + 12.How long does it take the rocket to reach the maximum height?

Answer 1

Answer:

76 feet

Explanation:

h = -16t^2 + 64t + 12

The maximum height will be reached after -b/2a secs

a = -16 , b = 64, c= 12

-b/2a = -64/2(-16)

= -64/-32

= 2 secs

The maximum height = -16(2)^2 + 64(2) + 12

= -16(4) + 128 + 12

= -64 + 128 + 12

= 76 ft

Explanation:

Answer 2

76 feet

Explanation:

h = -16t^2 + 64t + 12

The maximum height will be reached after -b/2a secs

a = -16 , b = 64, c= 12

-b/2a = -64/2(-16)

= -64/-32

= 2 secs

The maximum height = -16(2)^2 + 64(2) + 12

= -16(4) + 128 + 12

= -64 + 128 + 12

= 76 ft