The asteroid is 4.11 x 10¹¹ m far from Sun
Step-by-step explanation:
We have gravitational force

Where G = 6.67 x 10⁻¹¹ N m²/kg²
M = Mass of body 1
M = Mass of body 2
r = Distance between them
Here we have
M = Mass of Sun = 1.99×10³⁰ kg
m = Mass of asteroid = 4.00×10¹⁶ kg
F = 3.14×10¹³ N
Substituting

The asteroid is 4.11 x 10¹¹ m far from Sun