Question

A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson’s ratio of 0.35 is pulled in tension with force of 40,000 N. If the deformation is totally elastic, what is the strain experienced by the specimen?

Answer 1

0.00116

Step-by-step explanation:

Tensile modulus,
`E=\frac {Stress}{Strain}`

Making strain the subject then

`Strain=\frac {Stress}{E}`

Since
`stress=\frac {F}{A}` then

`Strain=\frac {F}{AE}=\frac {40000}{\pi 0.01^(2)* 110* 10^(9)}=0.00115749\approx 0.00116`