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Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma distribution with mean 40 weeks and variance 320 weeks.

A) What is the probability that a transistor will last between 1 and 40 weeks?

B) What is the probability that a transistor will last at most 40 weeks?

User Dtg
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1 Answer

4 votes

Answer:

a)
P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:


P(1 \leq X \leq 40)=0.560

b)
P(X \geq 40)=1-P(X<40)

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:


P(X \geq 40)=1-P(X<40)=0.440

Explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for
\alpha events to occur in a Poisson process with mean arrival time of
\beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:


\mu = 40 = \alpha \beta (1)


\sigma^2 =320= \alpha \beta^2 (2)

From this we can solve
\alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for
\alpha and we got:


\alpha= (40)/(\beta) (3)

And if we replace condition (3) into (2) we got:


320= (40)/(\beta) \beta^2 = 40 \beta

And solving for
\beta = 8

And now we can use condition (3) to find
\alpha


\alpha=(40)/(8)=5

So then we have the parameters for the Gamma distribution. On this case
X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:


P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:


P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:


P(X \geq 40)=1-P(X<40)

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:


P(X \geq 40)=1-P(X<40)=0.440

User Phoad
by
5.6k points