Answer:
D. fputs($someFile, $name);
Step-by-step explanation:
The instruction is not right as it is in the answer, because the content inside $name will be placed into the file referenced by $someFile. The correct structure is like this:
fputs($name, $someFile);
where:
- $name is the variable with the content to be inserted.
- $someFile is the file where the information is going to be saved.